Answer:
Number of year to get $10,000 as interest = 7.5 year (Approx)
Step-by-step explanation:
Given:
Initial investment = $20,000
Interest on investment = $10,000
Rate of interest = 5.6% = 0.056
Find:
Number of year to get $10,000 as interest:
Computation:
[tex]Interest\ on\ investment = Initial\ investment[(1+r)^n-1]\\\\10,000 = 20,000[(1+0.056)-1]\\\\0.5=(1.056)^n-1\\\\1.5 =(1.056)^n\\\\n=7.44[/tex]
Number of year to get $10,000 as interest = 7.44
Number of year to get $10,000 as interest = 7.5 year (Approx)