Answer:
v = 0.74 m / s
Explanation:
We can solve this exercise using the conservation of the moment
initial instant. Before the crash
p₀ = m v
where m is 2.50 kg and its velocity v₀ = 15 m / s
final moment. After catching the dough
[tex]p_{f}[/tex] = (m + M) v
As the system is made up of the mass and the person, all the forces during the impact are internal, therefore the moment is conserved
p₀ = p_{f}
m v₀ = (m + M) v
v = m / (m + M) v₀
we calculate
v = 2.5 / (2.5 + 48) 15
v = 0.74 m / s
