Answer:
[tex] T = \frac{1}{f}[/tex]
And replacing we got:
[tex] T = \frac{1}{34.5 Hz}= 0.0290 s[/tex]
And then we can conclude that with the conditions given the period of the string would be 0.0290 s
Step-by-step explanation:
For this case we know the frequency associated to the 4 harmonic.
We know that by definition the frequency is the inverse of the period:
[tex] f= \frac{1}{T}[/tex]
If we solve for the period we got:
[tex] T = \frac{1}{f}[/tex]
And replacing we got:
[tex] T = \frac{1}{34.5 Hz}= 0.0290 s[/tex]
And then we can conclude that with the conditions given the period of the string would be 0.0290 s
