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The battery has a voltage of 12V. R1 = R2 = 100Ω.

I1 = A I2 = A IT =

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0.360.240.830.120.060.120.006

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Answer:

FOR PARALLEL CONNECTION

I1 = 0.12A

I2 = 0.12A

IT =0.24A

FOR SERIES CONNECTION

I1 = I2 = 0.06A

IT =0.06A

Explanation:

According to ohms law, V =ITRt

V is the supply voltage

IT is the total current flowing in the circuit

Rt is the total equivalent resistance

Given R1= R2= 100Ω

V= 12V

FOR PARALLEL CONNECTION;

To calculate the total current IT in the battery, we need to calculate the total equivalent resistance RT first. For a parallel connected circuit, the equivalent resistance in the circuit is the sum of the reciprocal of its individual resistances as shown;

[tex]\frac{1}{RT} = \frac{1}{100} + \frac{1}{100}\\\frac{1}{RT} = \frac{2}{100} \\\frac{RT}{1} = \frac{100}{2}\\[/tex]

RT = 50Ω

from the equation above;

IT = V/RT

IT = 12/50

IT = 0.24A

Note that in a parallel connected circuit, different current flows through the resistances but the same voltage is across them.

IT = I1+I2

For current in resistance R1;

I1 = V/R1

I1 = 12/100

I1 = 0.12A

Since both resitance are the same, they will share the total current equally. Therefore I2 = 0.12A

FOR SERIES CONNECTION;

The total equivalent resistance in the circuit will be the sum of their individual resistances.

[tex]RT = R1+ R2[/tex]

RT = 100Ω+100Ω

RT = 200Ω

IT = V/RT

IT = 12/200

IT = 0.06A

Since the resistances are connected in series, the same current will flow through them but different voltages. The total current flowing in the circuit will be the same current flowing through the resistors.

Therefore I1 = I2 = 0.06A