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BRAINIEST ANSWER PLEASE HELP OFFERING 30 POINTS!!!!

Lulu tells her little brother, Jack, that she is holding 20 coins all of which are dimes and quarters. They have a value of $4.10. She says she will give him the coins if he can tell her how many of each she is holding. Algebraically solve this problem for Jack when x is # of dimes and y is the # of quarters

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Answer:

The answer is 14 quarters and six dimes

Step-by-step explanation:

-.1(D+Q=20)

.10D+.25Q=4.10    -.1D-.1Q=-2

                             .1D+.25Q=4.10

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                            .15Q=2.10/.15(both sides)

Q=14 which leaves you needing 60 more cents so 6 dimes

Answer:

6 dimes and 14 quarters

Step-by-step explanation:

x+y=20

0.1x+0.25y=4.1

We can multiply all the numbers in the second equation by 20 to get 2x+5y=82.

Then isolate y to get y=20-x.

Substitute y for 20-x in equation 2 to get 2x+5(20-x)=82

2x+100-5x=82

-3x+100=82

-3x=-18

x=6, and y=20-6, which is 14.

So, Lulu has six dimes and 14 quarters.

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