Answer:
Mass will be equal to 874.56 gram
Explanation:
Molar mass of sulfur = 32 u
Molar mass of Florine = 19 u
Therefore molar mass of [tex]SF_2[/tex] [tex]=32+2\times 19=70u[/tex]
So mass of [tex]6.023\times 10^{23}[/tex] particle is 70 gram
Therefore mass of 1 particle
[tex]=\frac{70}{6.023\times 10^{23}}=11.62\times 10^{-23}g[/tex]
Therefore mass of [tex]7.525\times 10^{24}[/tex] particle is
[tex]7.525\times 10^{24}\times 11.62\times 10^{-23}=874.56gram[/tex]
