Answer:
0.6
Step-by-step explanation:
Given that the spinner has 5 equal sections numbered 1 to 5.
- Total Sample Space, n(S)=5
Multiples of 2 in 1 to 5 are: {2,4}
Number less than than 3 are:{1,2}
Since we are required to find the probability of the spinner stopping on a number that is a multiple of 2 or is less than 3, we take the union of both sets.
{2,4} [tex]\cup[/tex] {1,2} ={1,2,4}
Number of Outcomes=3
Therefore,
Probability of the spinner stopping on a number that is a multiple of 2 or is less than 3 [tex]=\dfrac{3}{5}=0.6[/tex]
