The grades on a geometry midterm at Springer are roughly symmetric with u = 73 and 0 = 3.0.
Umaima scored 72 on the exam.
Find the z-score for Umaima's exam grade. Round to two decimal places.

Respuesta :

Answer:

z = - 0.33

Step-by-step explanation:

Given that:

Mean (μ) = 73, standard deviation (σ) = 3.0

Z score is a measure in statistics to determine the number of standard deviation a value is above or below the mean of what is measured. If the value is above the mean it is positive but if it is below the mean it is negative. It is given by the equation:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

To calculate z-score for Umaima's exam grade, we need to calculate the z score of 72

For x = 72, the z score is:

[tex]z=\frac{x-\mu}{\sigma}=\frac{72-73}{3} =-0.33[/tex]

z = - 0.33

Answer:

−0.33

Step-by-step explanation:

just did it oh khan