If we start with 1.000 g of strontium-90, 0.908 g will remain after 4.00 yr This means that half-life of strontium-90 is _________ yr.

A) 3.05

B) 4.40

C) 28.8

D) 3.63

E) 41.6

Respuesta :

Answer: C) 28.8

Explanation:

Expression for rate law for first order kinetics is given by:

[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]

where,

k = rate constant

t = age of sample

a = initial amount of the reactant  = 1.000 g

a - x = amount left after decay process = 0.908 g

a) to find rate constant

[tex]4.00yr=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]

[tex]k=\frac{2.303}{4.00}\log\frac{1.000}{0.908}[/tex]

[tex]k=0.024yr^{-1}[/tex]

b) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

[tex]t_{\frac{1}{2}}=\frac{0.693}{k}[/tex]

[tex]k=\frac{0.693}{0.024yr^{-1}}=28.8yr[/tex]

The half-life of strontium-90 is 28.8 yr.