Answer:
Amount of string let out by Jim will be 156.9 m.
Step-by-step explanation:
Distance between Jim and Patty = 200 m
Angle of elevation of the kite from Jim = 85°
Angle of elevation of the kite from Patty = 40°
Angle between the lines joining Jim and kite and Patty and the kite = 180° - (85 + 40)° = 55°
By applying Sine rule in the triangle formed by the kite, Jim and Patty,
[tex]\frac{\text{sin}55}{200}=\frac{\text{sin}40}{x}[/tex]
x = [tex]\frac{200\times \text{sin}40}{\text{sin55}}[/tex]
x = 156.94
≈ 156.9 m
Therefore, amount of string let out by Jim will be 156.9 m.
