If the specific heat of gold is 0.13 J/gC, what is the amount of energy (heat) required to raise 30.0g of gold from 15 degrees Celsius to 41 degrees Celsius?

Respuesta :

Answer: The amount of energy required is 101 Joules

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

[tex]Q=m\times c\times \Delta T[/tex]

Q = Heat absorbed = ?

m= mass of gold = 30.0 g

c = specific heat capacity of gold = [tex]0.13J/g^0C[/tex]

Initial temperature of the water = [tex]T_i[/tex] = 15°C

Final temperature of the water = [tex]T_f[/tex]  = 41°C

Change in temperature ,[tex]\Delta T=T_f-T_i=(41-15)^0C=26^0C[/tex]

Putting in the values, we get:

[tex]Q=30.0g\times 0.13J/g^0C\times 26^0C[/tex]

[tex]Q=101J[/tex]

The amount of energy required is 101 Joules