Answer:
Explanation:
Magnetic field due to current carrying wire at a distance r from the wire is
[tex]B=\frac{\mu_0I}{2r}---(1)[/tex]
In our case
[tex]I=\frac{I_0}{2}[/tex]
where,
I₀ = max current or peak current
and r = h (where h is the height of power line)
[tex]\therefore B=\frac{\mu (I_0/2)}{2h} \\\\=\frac{\mu_0 I_0}{4h} ----(2)[/tex]
put
h ≈ 370m
I₀ ≈ 3KA
[tex]B= \frac{(1.26*10^-^6)(3*10^3)}{4*(370)} \\\\=2.5*10^-^6 T[/tex]
