Answer:
(a)f(0)=-3
(b)f(1)=-1
(c)f(5)=7
(d)f(6)=211
Step-by-step explanation:
[tex]f(x)=\left\{\begin{array}{ccc}2x-3, &-2\leq x \leq 5 \\x^3-5, &5<x\leq6 \end{array}\right[/tex]
(a) f(0)
For x such that , [tex]-2\leq x \leq 5, f(x)=2x-3[/tex]
Since [tex]-2\leq 0\leq 5[/tex]
[tex]f(0)=2(0)-3=0-3\\f(0)=-3[/tex]
(b)f(1)
For x such that , [tex]-2\leq x \leq 5, f(x)=2x-3[/tex]
Since [tex]-2\leq 1\leq 5[/tex]
[tex]f(1)=2(1)-3=2-3\\f(1)=-1[/tex]
(c)f(5)
For x such that , [tex]-2\leq x \leq 5, f(x)=2x-3[/tex]
Since [tex]-2\leq 5\leq 5[/tex]
[tex]f(5)=2(5)-3=10-3\\f(5)=7[/tex]
(d)f(6)
For x such that [tex]5<x\leq6, f(x)=x^3-5[/tex]
[tex]f(6)=6^3-5\\f(6)=211[/tex]