Draw the image of △ABC under a dilation whose center is P and scale factor is 1/2

Answer:
Step-by-step explanation:
Let the point P is at the origin (0, 0).
Then the coordinates of A, B and C will be (8, 4), (-2, 2) and (4, -4) respectively.
Rule for the dilation of a point by a scale factor = k
(x, y) → (kx, ky)
If k = [tex]\frac{1}{2}[/tex]
Then, A(8, 4) → A'(4, 2)
B(-2, 2) → B'(-1, 1)
C(4, -4) → C'(2, -2)
Now we can plot the new image with points A', B' and C'
Following are calculation to the given points:
Given:
[tex]\Delta ABC[/tex] under a dilation whose center is P
scale factor [tex]= \frac{1}{2}[/tex]
To find:
points=?
Solution:
In the given question we assume that the origin at the point [tex]P(0, 0)[/tex].
therefore the coordinates of [tex]A, B, \ and \ C[/tex] would then be [tex](8, 4), (-2, 2), \ and\ (4, -4)[/tex] respectively.
Scale factor dilatation rule[tex]= k[/tex]
[tex](x, y) \to (kx, ky)[/tex]
If [tex]k = \frac{1}{2}[/tex]
Then,
[tex]A(8, 4) \to A'(4, 2)\\\\B(-2, 2) \to B'(-1, 1)\\\\C(4, -4) \to C'(2, -2)\\\\[/tex]
We can now draw a new picture with the points [tex]A', B', \ and\ C'[/tex], please find the attached file.
Learn more:
brainly.com/question/16967942