Answer:
$9197.72
Explanation:
To find the amount to be spent for the brake if the Minimum Attractive Rate of Return is 10% compounded annually, we have the following:
Cost incurred without the brake = Number of pieces * (Number of minutes for producing one product / total number of minute in an hour) * cost per peice
Where,
Number of minutes for producing a product without the brake system =
105 seconds(1 min, 45 sec) + 15 seconds(coast time) = 2 minutes or 120 seconds
Thus,
Cost incurred without break is =
[tex]50,000* \frac{2}{60}* (10 + 5) = 25,000 [/tex]
Let's find the number of minutes for installing a break
= 105 + 3 seconds = 108 seconds = 1.8 minutes
Cost incurred with break =
[tex] 50,000 * \frac{1.8}{60} * (10 + 5) = $ 22,500 [/tex]
To find the maintainence cost, let's consider parts & material cost and labor cost for operator
[tex] (\frac{50000 * \frac{1.8}{60}}{589}) * (\frac{30}{60} * (10+48)) = 73.85 [/tex]
No. of years the brake will last
[tex] = \frac{\frac{7500}{50000}}{1.8/60} = 5 years [/tex]
The maximum amount that can be spent on brake will be the difference in cost incurred with brake and without brake * present value of annuity factor of 5 years at 10%
= (25,000 - 22,573.85)*PVAF, 10% for 5 years = $9197.72
$9198 (rounded off)
The the amount to be spent for the brake if the Minimum Attractive Rate of Return is 10% compounded annually is $9197.72
