Answer:
0.93L
Explanation:
We'll begin by calculating the number of mole of present 374g of KNO3. This is illustrated below:
Mass of KNO3 = 374g
Molar mass of KNO3 = 39 + 14 + (16x3) = 101g/mol
Number of mole of KNO3 =..?
Mole = Mass /Molar Mass
Number of mole of KNO3 = 374/101 = 3.7 moles
Now, we can calculate the volume of the solution as follow:
Mole of KNO3 = 3.7 moles
Molarity = 4M
Volume =..?
Volume = mole /Molarity
Volume = 3.7/4
Volume = 0.93L
Therefore, the volume of the solution is 0.93L
Answer:
THE VOLUME OF A 4 M SOLUTION THAT CONTAINS 374 g OF KNO3 IS 0.93 L
Explanation:
Number of moles = concentraion * volume
Number of moles can also be written as:
number of moles = mass / molar mass
Calculate the molar mass of KNO3 where (K = 39, N = 14, 0=16)
molar mass of KNO3 = (39 + 14 + 16*3) = 101 g/mol
So therefore:
mass / molar mass = concentration * volume
where;
mass = 374 g
molar mass = 101 g/mol
concentration = 4 M
volume = unknown
Hence,
374 / 101 = 4 * V
V = 374 / 101 * 4
V = 374 / 404
V = 0.9257 dm3
The volume of a 4M solution that contains 364 g of KNO3 is approximately 0.93 L
