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Ask the user to enter a number for red, green, and blue components of an RGB value. Test to make sure each value is between 0 and 255 inclusive. If a color's value is out of range, print which component is not correct (e.g., "Red number is not correct" if the red value is 300). Multiple colors may be out of range.

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teobguan2019

Answer:

  1. r = int(input("Enter a number for red channel: "))
  2. g = int(input("Enter a number for green channel: "))
  3. b = int(input("Enter a number for blue channel: "))  
  5. if(r < 0 or r >255):
  6.    print("Red number is not correct.")
  8. if(g < 0 or g >255):
  9.    print("Green number is not correct.")
  11. if(b < 0 or b >255):
  12.    print("Blue number is not correct.")

Explanation:

The solution code is written in Python.

Firstly, prompt user to input three numbers for red, green and blue (Line 1-3).

Next, create three similar if statements to check if the red, green and blue are within the range 0-255 by using logical operator "or" to check if the number is smaller than 0 or bigger than 255. If either one condition is met, display a message to indicate a particular color number is not correct (Line 5-12).

fichoh

The program written in python 3 which displays the whether the range of RGB values inputted by the user is in range goes thus :

r = int(input('Enter red value between 0 - 255'))

g = int(input('Enter green value between 0 - 255'))

b = int(input('Enter blue value between 0 - 255'))

#accepts inputs for red, green and blue values from the user

vals = {'red':r, 'green':g, 'blue':b}

#read the values into a dictionary and assign the values inputted by the user as the values

for k, v in vals.items():

#iterate through the dictionary as key-value pairs

if(v < 0) or (v > 255):

#Check of the values inputted is within range (0 - 255)

print('%s is not correct' %k)

#for any value which is out of range, display the name of the color and state that it is incorrect.

A sample run of the program ls attached below.

Learn more :https://brainly.com/question/18802298

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