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1. Potassium (K) has an atomic mass of 39.0983 amu and only two naturally-occurring isotopes. The K-41 isotope (40.9618 amu) has a natural abundance of 6.7302%. What is the mass (in amu) of the other isotope

Respuesta :

Answer:

38.96383282 amu

Explanation:

39.0983 = (40.9618 [tex]\times[/tex] 0.067302) + ( ? [tex]\times[/tex] (1-0.067302)

39.0983 = 2.756811064 + ( ? [tex]\times[/tex] 0.932698)

subtract 2.756811064 from both sides

36.34148894 = ( ? [tex]\times[/tex] 0.932698)

divide both sides by 0.932698

? = 38.96383282 amu

lincolndaly26

Answer:

38.96383282 amu

Explanation:

39.0983 = (40.9618  0.067302) + ( ?  (1-0.067302)

39.0983 = 2.756811064 + ( ?  0.932698)

subtract 2.756811064 from both sides

36.34148894 = ( ?  0.932698)

divide both sides by 0.932698

? = 38.96383282 amu

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