Answer:
[tex]y=sin^{-1}x[/tex]
Step-by-step explanation:
Given: A point is [tex](0,2\pi)[/tex]
To find: function whose graph passes through the given point
Solution:
A trigonometry explains the relationship between the sides and the angles of the triangle.
The inverse trigonometric functions [tex]sin^{-1}x\,,\,cos^{-1}x\,,\,tan^{-1}x[/tex] help to find the value of an unknown angle of a right triangle when length of two sides are given.
Consider [tex]\sin y=x[/tex]
Put [tex]y=2\pi[/tex]
[tex]sin 2\pi=0[/tex]
So, point [tex](0,2\pi)[/tex] satisfies the function [tex]y=sin^{-1}x[/tex]
Therefore, graph of function [tex]y=sin^{-1}x[/tex] passes through [tex](0,2\pi)[/tex]
