Answer:
Set of ordered pairs = { ( 0 , 2 ), ( π / 2 , 0) , ( π , -2) , ( 2 π , 2)}
Step-by-step Explanation:
Given y = 2 cos x
i) Let x =0 ⇒ y = 2 cos (0) = 2
The ordered pair ( 0 , 2 )
ii) Let x = π / 2 ⇒ y = 2 cos (π/2) = 2(0) =0
The ordered pair ( π / 2 , 0)
iii) let x = π ⇒ y = 2 cos(π) = 2 (-1) = -2
The ordered pair ( π , -2)
iv)
let x = 2π ⇒ y = 2 cos(2π) = 2 (1) = 2
The ordered pair ( 2 π , 2)
Set of ordered pairs = { ( 0 , 2 ), ( π / 2 , 0) , ( π , -2) , ( 2 π , 2)}
