Answer:
[tex] \boxed{y = 3} [/tex]
Step-by-step explanation:
[tex] = > \frac{5 - 7y}{2 + 4y} = - \frac{8}{7} \\ \\ = > 7(5 - 7y) = - 8(2 + 4y) \\ \\ = > (7 \times 5) - (7 \times 7y) = ( - 8 \times 2) + ( - 8 \times 4y) \\ \\ = > 35 - 49y = - 16 - 32y \\ \\ = > 35 - 49y + 32y = - 16 \\ \\ = > 35 - 17y = - 16 \\ \\ = - 17y = - 16 - 35 \\ \\ = > \cancel{- }17y = \cancel{- } 51 \\ \\ = > 17y = 51 \\ \\ = > y = \frac{51}{17} \\ \\ = > y = 3[/tex]
