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Solve by taking the square root of both sides 3(x-1)^2-162=0
a. x = -1 - 3 sqrt 6 or -1 + 3 sqrt 6
b. x = 1 - 3 sqrt 6 or -1 + 3 sqrt 6
c. x = -1 - 3 sqrt 6 or 1 + 3 sqrt 6
d. x = 1 - 6 sqrt 6 or 1 + 6 sqrt 6

Respuesta :

Answer:

see explanation

Step-by-step explanation:

Given

3(x - 1)² - 162 = 0 ( add 162 to both sides )

3(x - 1)² = 162 ( divide both sides by 3 )

(x - 1)² = 54 ( take the square root of both sides )

x - 1 = ± [tex]\sqrt{54}[/tex] = ± 3[tex]\sqrt{6}[/tex] ( add 1 to both sides )

x = 1 ± 3[tex]\sqrt{6}[/tex]

x = 1 - 3[tex]\sqrt{6}[/tex] or x = 1 + 3[tex]\sqrt{6}[/tex]

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