Determine the attributes of the hyperbola represented by this equation:
(y-21)^2/20^2-(x+20)^2/21^2=1

The vertices are A: (-41,21) and (1,21), B: (-20,0) and (-20,42), C: (-20,1) and (-20,41), D: (20,1) and (20,41).
The foci are A; (-50,21) and (10,21), B: (-20,-8) and (-20, 50), C: (-20,-10) and (-20,52), D; (20,-8) and (20,42)

The vertices of the hyperbola will be (–20, 41) and (–20, 1). Then the correct option is C. The foci of the hyperbola will be (–20, 50) and (–20, –8). Then the correct option is B.

What is a hyperbola?

The hyperbola is the locus of a point such that the difference of distance from point P to two non-movable points. These two points are called foci of hyperbola.

The equation of the hyperbola is given below.

[tex]\rm \dfrac{(y-21)^2}{20^2}-\dfrac{(x+20)^2}{21^2}=1[/tex]

The vertices (h, k + a), (h, k – a) are the two bending points of the hyperbola with center (h, k).

The center of the hyperbola will be at (-20, 21).

The value of a and b will be 20 and 21, respectively.

Then the vertices of the hyperbola will be

(–20, 21 + 20) and (–20, 21 – 20)

(–20, 41) and (–20, 1)

Then the correct option is C.

The foci (h, k + c), (h, k – c) are the two bending points of the hyperbola with center (h, k).

c² = a² + b²

c² = 20² + 21²

c = 29

Then the foci of the hyperbola will be

(–20, 21 + 29) and (–20, 21 – 29)

(–20, 50) and (–20, –8)

Then the correct option is B.

More about the hyperbola link is given below.

https://brainly.com/question/12919612

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