The charge that is moved is required.
The magnitude of charge moved is option 4. [tex]2\times 10^{-3}\ \text{C}[/tex]
V = Potential difference = 10.0 V
W = Work done = [tex]2\times10^{-2}\ \text{J}[/tex]
q = Magnitude of charge
When work done on moving a charge is divided by the potential difference we get the magnitude of the charge that is moved.
The charge of an object is the result of an excess or a lack of positive or negative charges on a body.
So, the magnitude of charge is given by
[tex]q=\dfrac{W}{V}\\\Rightarrow q=\dfrac{2\times 10^{-2}}{10}\\\Rightarrow q=2\times 10^{-3}\ \text{C}[/tex]
Learn more about potential difference:
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