Answer:
Option D
Step-by-step explanation:
[tex]4(5 + 3) = 2(22 -6)\\\boxed{\text {For the first part of the equation:}}\\\\4(5+3)\\\\=> 4*5 = 20\\=> 4*3 = 12\\\\\boxed{4(5+3)=20+12}\\\\\\\boxed{\text {For the second part of the equation:}}\\\\2(22-6)\\\\=> 2*22=44\\=> 2*-6 = -12\\\\\boxed{2(22-6)=44-12}\\\\\text {Put the two parts together, and we get:}\\\huge{\boxed{20+12=44-12}[/tex]
