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Which polynomial function has a root of 3 with multiplicity 2 and roots of –10 and –1 with multiplicity 1? f(x) = (x – 10)(x – 1)(x + 3)(x + 3) f(x) = x(x – 10)(x – 1)(x + 3) f(x) = (x + 10)(x + 1)(x – 3)(x – 3) f(x) = x(x + 10)(x + 1)(x – 3)(x – 3)

Respuesta :

wegnerkolmp2741o

Answer:

 (x+10)(x+1)( x-3) ( x-3)

Step-by-step explanation:

root of 3 with multiplicity 2

( x-3) ^2 or ( x-3) ( x-3)

root of -10

(x- -10)  is (x+10)

root of -1

(x - -1) is (x+1)

( x-3) ^2 (x+10)(x+1)

Answer:

C) f(x) = (x + 10)(x + 1)(x – 3)(x – 3)

Step-by-step explanation:

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