Respuesta :
Answer:
A) N = (M + mf + md) g
B) d = md L / (2 mf)
Explanation:
Draw a free body diagram. There are four forces acting on the board.
Weight force M g pulling down at the center of the board.
Normal force N pushing up at the center of the board.
Weight force mf g pulling down a distance d from the center.
Weight force md g pulling down at the end of the board.
Sum of forces in the y direction:
∑F = ma
N − M g − mf g − md g = 0
N = (M + mf + md) g
Sum of moments about the center of the board:
∑τ = Iα
md (L/2) − mf d = 0
d = md L / (2 mf)
The magnitude of the upward force n exerted by the support on the board will be the same with the magnitude of the weight of the seesaw. Which is
W = 9.8M Newton
The father should sit at L/4 at the other end in order to balance the system at rest
Since the seesaw is of a uniform board, the center of gravity will act at the center. If it is of length L, the support called the fulcrum will be positioned at L/2.
If the daughter is a distance L/2 from the center, Then, she must be positioned at L/4 from the one edge of the board.
A. The magnitude of the upward force n exerted by the support on the board will be the same with the magnitude of the weight of the seesaw. Which is
W = mg
W = 9.8M Newton
The weight of both the father and the daughter will act downward. so, they will not be included.
The father should sit at L/4 at the other end in order to balance the system at rest
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