Answer:
The new force between charges is 2 N.
Explanation:
It is given that, a 3 C charge and a 6 C charge feel 4 N of force between them.
The force between charges is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
r is distance between charges
Original force is :
[tex]4=\dfrac{k(3)(6)}{r^2}\ ....(1)[/tex]
If the 6 C is replaced with a 3 C, new force between them is given by :
[tex]F'=\dfrac{k(3)(3)}{r^2}\ ....(2)[/tex]
Dividing equation (1) and (2) we get :
[tex]\dfrac{4}{F'}=\dfrac{2}{1}\\\\F'=2\ N[/tex]
So, the new force between charges is 2 N.
