Answer:
RootIndex 6 StartRoot 432 EndRoot
Step-by-step explanation:
To find the following product
[tex] \sqrt[3]{4} \times \sqrt{3} [/tex]
we can rewrite the radicals and then replace them into the multiplication, as follows:
[tex] \sqrt[3]{4} = 4^{\frac{1}{3}} = 4^{\frac{1}{3} \times \frac{2}{2}} = 4^{\frac{2}{6} = \sqrt[6]{16}[/tex]
[tex] \sqrt{3} = 3^{\frac{1}{2}} = 3^{\frac{1}{2} \times \frac{3}{3}}} = 3^{\frac{3}{6}} = \sqrt[6]{27} [/tex]
[tex] \sqrt[3]{4} \times \sqrt{3} = \sqrt[6]{16} \times \sqrt[6]{27} = \sqrt[6]{16 \times 27} = \sqrt[6]{432} [/tex]
