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Mr. Lim and Mr. Tay had $31 090 at first.Mr. Lim donated $2390 of his money and Mr. Tay spent half of his money on a holiday trip. As a result, Mr. Lim had 3 times as much money as Mr. Tay. How much money did Mr. Lim have at first?

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Answer:

Mr.Lim had 19610 dollars, and Mr.Tay had 11480 dollars at first.

Step-by-step explanation:

Mr. Lim had 19610 dollars at first.

To find how much did Mr. Lim had at first.

Given:

Mr. Lim and Mr. Tay had $31 090 at first.

Mr. Lim donated $2390 of his money and

Mr. Tay spent half of his money on a holiday trip.

Mr. Lim had 3 times as much money as Mr. Tay.

Step 1:

Let Mr. Tay had x

Let Mr. Lim had y

x + y=31090………..(1)

Step 2:

Mr. Tay spent on holiday = x + 2390/2

Money left with Mr. Lim = y - 2390

Given,

y - 2390 = 3(x + 2390/2) .............(2)

Step 3:

Equating equation (1) and (2)

we get,

x = 11480

y = 19610

Hence, Mr. Lim has $19610, and Mr. Tay had $11480 dollars at first.

To learn how to calculate the amount spent, refer,

  • https://brainly.com/question/2263981

#SPJ2

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