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Can someone help me I was doing good and then I got stuck on this question what I can’t figure out is how you get the voltage when you only have the watt and resistance .

A 60.0 Watt lightbulb has an operating resistance of 220 Ω.

Calculate the operating voltage of this lightbulb.

Respuesta :

Person80

Answer:

114.89 V

Step-by-step explanation:

Watts are a measure of power, and there is an equation that relates power, voltage, and resistance. It goes like this:

P=(V^2)/R

Now to find the voltage you want to solve for V

PR = V^2

V = [tex]\sqrt{PR}[/tex]

Now substitute your numbers into the equation and you get your answer

V = [tex]\sqrt{(60)(220)}[/tex]

V = [tex]\sqrt{13200}[/tex]

V = 114.89 V

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