Answer:
Probability that X <32 degrees
[tex]=P(Z<\frac{32-22}{6}) =P(Z<1.67)\\ = 0.9522[/tex]
Convert this into percent by multiplying by 100
95.22% of days in February has minimum temperatures below freezing (32 degrees Upper F )
Step-by-step explanation:
Given that a city's mean minimum daily temperature in February is 22 degrees Upper F, with std deviation 6 degrees.
Let X be the minimum temperature in February
Then X is N(22,6)
To calculate percentage of days in February has minimum temperatures below freezing (32 degrees Upper F )
Probability that X <32 degrees
[tex]=P(Z<\frac{32-22}{6}) =P(Z<1.67)\\ = 0.9522[/tex]
Convert this into percent by multiplying by 100
95.22% of days in February has minimum temperatures below freezing (32 degrees Upper F )
