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A rectangular piece of metal is 25in longer than it is wide . Squares with sides 5in long are cut from the four corners and the flaps are folded upward to form an open box. If the volume of the box is 750in, what were the original dimensions of the piece of metal

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Answer:

Step-by-step explanation:

Let width be x

Let lenght be 25 + x

Total ax = (25+x) * x

Square with 5in long are cut from the four corner formed = 750in

(25+x-10) * (x-10) * 5 = 750

(15+x) (x-10) = 150

15x-150+x^2-10x =150

15x -150-150+x^2-10x+0

x^2+15x-300=0

(ax^2+bx+c=0)

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