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Solve Systems of Algebraic Equations in Two Variables
Hello I need some help on setting up 2 equations of this problem. The answers are cheeseburger costs $1.55 and the milkshake $0.85

Four cheeseburgers and two chocolate milkshakes cost a total of $ 7.90. Two
Shakes cost 15 cents more than a hamburger with
cheese so What is the price of a cheeseburger?
And the price of a shake?

Respuesta :

wegnerkolmp2741o

Answer:

4c+ 2m = 7.90

2m -.15 = c

Step-by-step explanation:

Let c = cheese burger

m = milkshake

4c+ 2m = 7.90

2m -.15 = c

Substitute into the first equation

4( 2m -.15) +2m = 7.90

Distribute

8m -.6 +2m = 7.90

Combine like terms

10m - .6 = 7.90

Add .6 to each side

10m = 7.90+.6

10m = 8.50

Divide by m

10m = 8.50/10

m = .85

Now find c

2m -.15 = c

2(.85) - .15=c

1.70-.15 = c

1.55 =c

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