Answer:
Step-by-step explanation:
How many quarts of a 50% solution of acid must be added to 20 quarts of a 20% solution of acid to obtain a mixture containing a 40% solution of acid? Answer: quarts
let x = amount of the 50% solution
A typical mixture equation using the decimal equivalent to
0.50x +0 .20(20) =0 .40(x+20)
0.50x + 4 = 0.40x + 8
0.50x - 0.40x = 8 - 4
0.10x = 4
x = 4/0.1
x = 40 qts of 50% solution
Hence 40 quarts of 50% solution must be added.
