Respuesta :

osikbro

Answer:

(-2,0) and (2,0)

Step-by-step explanation:

To find the x intercepts of a graph, you need to set the y to 0. This is because a graph only intersects the x axis at the line y=0. Hence:

[tex]4x^2-16=0[/tex]

Factor:

[tex]4(x^2-4)=0 \\\\4(x-2)(x+2)=0 \\\\x=2,-2[/tex]

The x intercepts are at (-2,0) and (2,0). Hope this helps!

wegnerkolmp2741o

Answer:

The x intercepts are -2 and 2

Step-by-step explanation:

y=4x^2-16

Set equal to zero to find the x intercepts

0 =4x^2-16

Factor

0 = 4(x^2 -4)

Factor again, noticing the difference of squares ( a^2 - b^2) = (a-b)(a+b)

0 = 4(x-2) (x+2)

Using the zero product property

0 = x-2   0 = x+2

x =2          x = -2

The x intercepts are -2 and 2

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