Consider the intermediate equations: 3 equations.

C(s) + O2(g) --> CO2(g) Delta H1 = -393.5 kJ

2CO(g) + O2(g) --> 2CO2(g) Delta H2 = -566.0 kJ

2H2O(g) --> 2H2(g) + O2(g) Delta H3 = 483.6 kJ

With the overall reaction:

C(s) + H2O(g) --> CO(g) + H2(g) Delta Hrxn = ?

QUESTION 1:

What must be done to calculate the enthalpy of reaction?

The first must be halved.

The first must be reversed.

The second must be halved.

The second must be reversed.

The third must be halved.

The third must be reversed.

QUESTION 2:

What is the overall enthalpy of reaction?

Delta Hrxn = ____ kJ

Respuesta :

Answer:

C. The second equation must be halved

D. The second equation must be reversed

E. The third equation must be halved.

Delta Hrxn= 131.3 kJ

Explanation:

The correct answer is -582 KJ.

What is the enthalpy of reaction?

  • Enthalpy is the heat content of a system.
  • The enthalpy change of a reaction is roughly equivalent to the amount of energy lost or gained during the reaction.
  • A reaction is favored if the enthalpy of the system decreases over the reaction.

What is the overall enthalpy of the reaction?

  • Equal to the sum of the standard enthalpies of the intermediate reaction steps is called overall enthalpy

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