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At the gym, Polina put 4 five-pound weights onto a barbell that weighed 22 pounds without any weights on it. If Polina lifted the barbell with both arms, which expression can be used to determine the weight that each arm was lifting?

[(4 × 5) ÷ 2] + 22
(4 × 5) ÷ 2 + 22
[22 + 4 × 5] ÷ 2
22 + (4 × 5) ÷ 2

Respuesta :

adioabiola

Answer:

D. 22+(4×5)÷2

Step-by-step explanation:

Four 5 pound weight=(4×5)

Barbell weighed 22 pounds

={(4×5)+22}

Paulina lifted it with both arms

Both arms=2

{(4*5)+22}/2

It can be rewritten as

22+(4*5)÷2

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