The coordinates of point B on line AC is (6/7, -30/7).
Given that, A(6, -6), C(-6,-2) and AB= 3/4 AC.
The section formula is P(x, y)[tex]=(\frac{mx_{2} +nx_{1}}{m+n}, \frac{my_{2} +ny_{1}}{m+n} )[/tex].
Now, AB= 3/4 AC⇒AB:AC=3:4
P(x,y)[tex]=(\frac{3(-6)+4(6)}{3+4}, \frac{3(-2) +4(-6)}{3+4} )[/tex]
=(6/7, -30/7)
Therefore, the coordinates of point B on line AC is (6/7, -30/7).
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