Answer:
14,850 ways
Step-by-step explanation:
Since the order does not matter, the number of possible committees is given by the product of the combination of picking 2 out of 10 faculty members and the combination of picking 4 out of 11 students:
[tex]n= \frac{10!}{(10-2)!2!}* \frac{11!}{(11-4)!4!}\\n=\frac{10*9}{2}*\frac{11*10*9*8}{4*3*2*1}\\n=14,850[/tex]
The committee can be formed in 14,850 ways