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Horses varied directly as goats and inversely as pigs squared. When the barnyard contained 5 horses there were 4 pigs and only 2 goats. How many goats went with 6 pigs and 10 horses?

Respuesta :

jazybearr

Answer:

I believe the answer is four there is twice as many horses so you would double the amount of original goats.

The number of goats that went with 6 pigs and 10 horses is; 4 goats.

Let the number of horses be h.

Let the number of pigs be p

Let the number of goats be g.

We are told that horses vary directly as goats.

Thus;

h ∝ g

Thus; h = k1g - --(eq 1)

Also, we are told that horses varies inversely as pigs squared.

Thus;

h ∝ 1/p²

h = k2/p² - - - (eq 2)

Where k1 and k2 are constant of proportionality.

When there are 5 horses there are 2 goats. Thus;

5 = 2k1

k1 = 5/2

k1 = 2.5

When there are 10 horses, we will have;

10 = 2.5g

g = 10/2.5

g = 4

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