Answer: [tex]\bold{2)\ sin\ C=\dfrac{20}{29}\qquad 3)\ tan\ A=\dfrac{8}{15}\qquad 4)\ tan\ Z=\dfrac{4}{3}}[/tex]
Step-by-step explanation:
[tex]2) \sin C=\dfrac{\text{side opposite of}\ \angle C}{\text{hypotenuse of triangle}}=\large\boxed{\dfrac{20}{29}}\\\\\\3) \tan A=\dfrac{\text{side opposite of}\ \angle A}{\text{side adjacent to}\ \angle A}=\large\boxed{\dfrac{8}{15}}\\\\\\4) \tan Z=\dfrac{\text{side opposite of}\ \angle Z}{\text{side adjacent to}\ \angle Z}=\dfrac{40}{30}\quad \rightarrow \large\boxed{\dfrac{4}{3}}[/tex]
