What is the height of this isosceles triangle?

Answer:
height ≈ 11.9 units
Step-by-step explanation:
Construct a perpendicular bisector from the vertex to the base, thus splitting the triangle into 2 right triangles.
Using the sine ratio in one of these right triangles, then
sin48° = [tex]\frac{opposite}{hypotenuse}[/tex] ( the opposite is the height h )
sin48° = [tex]\frac{h}{16}[/tex] ( multiply both sides by 16 )
16 × sin48° = h , thus
h ≈ 11.9 ( to the nearest tenth )