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Please help! Correct answer only!


At a carnival, there is a game where you can draw one of 20 balls from a bucket. The balls are numbered from 1 to 20. If the number on the ball is odd, you win $31. If the number on the ball is even, you win nothing. If you play the game, what is the expected payoff?

$____

Please help Correct answer onlyAt a carnival there is a game where you can draw one of 20 balls from a bucket The balls are numbered from 1 to 20 If the number class=

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Answer:

Expected Payoff ⇒ $ 15.5 ; Type in 15.5

Step-by-step explanation:

Considering that all odd out of the 20 numbers will have a probability of winning a 31 dollar prize, take a proportionality into account;

[tex]20 - Total Number of Balls,\\1 - 20 - Numbering of Balls,\\Even = Odd, Between 1 - 20, Knowing 20 - Even,\\\\10 / 20 - Odd,\\10 / 20 - Even,\\1 / 2 - Probability of Choosing an Odd Ball,\\\\Proportionality - 1 / 2 = x / 31, where x = " Expected Payoff ",\\1 / 2 = x / 31 - Cross Multiply,\\2x = 31,\\\\Conclusion ; x = 15.5 dollars[/tex]

Thus, Solution ; Expected Payoff ⇒ $ 15.5

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