Answer:
Yes, k is lower bound for the real zeros of the function.
Step-by-step explanation:
Lower Bound Theorem:
If you divide a polynomial function f(x) by (x - k), where k < 0, using synthetic division and this yields alternating signs, then k is a lower bound to the real roots of the equation f(x) = 0.
Given;
4x³ - 2x² + 2x + 4
k = -1
synthetic division;
-1 ] 4 -2 2 4
↓ -4 6 -8
---------------------------------------------
4 -6 8 -4
(the result has alternating signs, hence k is lower bound)
Thus, k is lower bound for the real zeros of the function.
