Respuesta :
Answer:
The target inventory position is T= 713.6 gallons.
Explanation:
Given:
Average demand =per day = D = 152 Gallons
Standard deviation of demand = σ = 33 Gallons per day
Lead time for delivery = L = 4 days
Z value for 94.5% service level = 1.6
The target inventory position = (Average demand x Lead time) + Safety stock
= (D × L) + (Z× σ × [tex]\sqrt{L}[/tex])
= (152 × 4) + (1.6 × 33 × [tex]\sqrt{4}[/tex])
= (152 × 4) + (1.6 × 33 × 2)
= 608 + 105.6
= 713.6
The value of the target inventory position will be 713.6 gallons.
The following can be illustrated from the information given:
- Average demand per day, D = 152
- Standard deviation of demand, σ = 33
- Lead time for delivery, L = 4
- Z value for 94.5% service level = 1.6
Therefore, the target inventory position will be:
= (Average demand x Lead time) + Safety stock
= (D × L) + (Z× σ × ✓L )
= (152 × 4) + (1.6 × 33 × ✓4 )
= (152 × 4) + (1.6 × 33 × 2)
= 608 + 105.6
= 713.6
Therefore, the target inventory position will be 713.6 gallons.
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