Answer:
[tex] p =\frac{7}{51}= 0.1372[/tex]
And then the probability that is NOT from sport temas using the complement rule is given by:
[tex] q = 1-p =1- \frac{7}{51}= 0.8627[/tex]
And if we convert that into % we got:
[tex] 0.8627 *100= 86.27\%[/tex]
Approximately 86.27% of the floats were NOT sports teams
Step-by-step explanation:
For this case we can begin finding the % of floats that were from sport tems using the Laplace definition of probability given by:
[tex]p = \frac{Possible}{Total}[/tex]
And replacing we got:
[tex] p =\frac{7}{51}= 0.1372[/tex]
And then the probability that is NOT from sport temas using the complement rule is given by:
[tex] q = 1-p =1- \frac{7}{51}= 0.8627[/tex]
And if we convert that into % we got:
[tex] 0.8627 *100= 86.27\%[/tex]
Approximately 86.27% of the floats were NOT sports teams