Answer:
The length of the second line is [tex]9\frac{1}{15}[/tex] inches
Step-by-step explanation:
Given
Length of first line = [tex]6\frac{4}{10}[/tex] inches
Length of second line = [tex]2\frac{2}{3}[/tex] inches longer
Required
Length of second line.
Let the length of the second line be represented by x.
From the question, x is [tex]2\frac{2}{3}[/tex] inches longer than the first line;
This implies that:
[tex]x = 2\frac{2}{3} + 6\frac{4}{10}[/tex]
Convert both fractions to improper fractions
[tex]x = \frac{8}{3} + \frac{64}{10}[/tex]
Take LCM
[tex]x = \frac{80 + 192}{30}[/tex]
[tex]x = \frac{272}{30}[/tex]
Convert to mixed fraction
[tex]x = 9\frac{2}{30}[/tex]
Reduce fraction to lowest term
[tex]x = 9\frac{1}{15}[/tex]
Hence, the length of the second line is [tex]9\frac{1}{15}[/tex] inches
