Answer:
[tex]=\frac{27y^9}{x^3}[/tex]
Step-by-step explanation:
[tex]\left(\frac{3x^2y^3}{x^3}\right)^3\\\mathrm{Apply\:exponent\:rule}:\quad \left(\frac{a}{b}\right)^c=\frac{a^c}{b^c}\\\left(\frac{3x^2y^3}{x^3}\right)^3=\frac{\left(3x^2y^3\right)^3}{\left(x^3\right)^3}\\=\frac{\left(3x^2y^3\right)^3}{\left(x^3\right)^3}\\\mathrm{Simplify}\:\left(3x^2y^3\right)^3:\quad 27x^6y^9\\=\frac{27x^6y^9}{\left(x^3\right)^3}\\\mathrm{Simplify}\:\left(x^3\right)^3:\quad x^9\\=\frac{27x^6y^9}{x^9}\\\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=\frac{1}{x^{b-a}}[/tex]
[tex]\frac{x^6}{x^9}=\frac{1}{x^{9-6}}\\\frac{x^6}{x^9}=\frac{1}{x^{9-6}}\\=\frac{27y^9}{x^{9-6}}\\\mathrm{Subtract\:the\:numbers:}\:9-6=3\\=\frac{27y^9}{x^3}[/tex]
