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If a gas has a pressure of 1.69 atm at a temperature of 300 K, what will the pressure change to if the container is cooled to 100 K?

Also

If a gas has a pressure of 715 mm Hg at the temperature of 500 K, what will the pressure change to if the container is heated to 900 K?

The pressure has been reduced with the cooling of the container, and the change in pressure has been 1.06 atm. The pressure has been increased with the heating of the container and the change in pressure has been 572 mm Hg.

Assuming the gas has been following the ideal behavior. According to the ideal gas equation,

PV =nRT

If the same gas has been heated, the n and R will be constant, as well as with the constant volume of initial and final pressure, the relationship to the P and T can be given as:

[tex]\rm \dfrac{Initial\;pressure}{Initial\;temperature}\;=\;\dfrac{Final\;pressure}{Final\;temperature}[/tex]

(a) For the gas with an initial pressure of 1.69 atm, the final pressure will be:

[tex]\rm \dfrac{1.69}{300}\;=\;\dfrac{Final\;Pressure}{100}[/tex]

Final pressure = 0.563 atm.

The change in pressure = Initial pressure - Final pressure

The change in pressure = 1.63 - 0.563 atm

The change in pressure = 1.06 atm.

The pressure has been reduced with the cooling of the container, and the change in pressure has been 1.06 atm.

(b) For the gas at initial pressure 715 mm Hg, the final pressure will be:

[tex]\rm \dfrac{715}{500}\;=\;\dfrac{Final\;Pressure}{900}[/tex]

Final pressure = 1,287 mm Hg.

The change in pressure = Final pressure - Initial pressure

The change in pressure = 1,287 - 715 mm Hg

The change in pressure = 572 mm Hg

The pressure has been increased with the heating of the container and the change in pressure has been 572 mm Hg.

For more information about the change in pressure, refer to the link:

https://brainly.com/question/12152879